GROUP BY is working.

src/queries.js

@@ -8,18 +8,14 @@ export function escape_regex(s) {
 export function do_image_query(query, database, collection_path, collection_thumbs_path) {
     return new Promise(function (resolve, reject) {
         var queries = [];
-        var ids = []; // TODO: this is for always uniquifying because of GROUP BY apparent bug in AlaSQL
         queries.push(query);
         database.queries_async(queries).then(res => {
             var photos = [];
             if (res && Array.isArray(res)) {
                 res.forEach(row => {
-                    if (!ids.includes(row["id"])) { //uniquify
-                        ids.push(row["id"]); //uniquify
-                        var imagepath = process.env.PUBLIC_URL + collection_path + "/" + row["relativePath"] + "/" + row["name"];
-                        var thumbpath = process.env.PUBLIC_URL + collection_thumbs_path + "/" + row["uniqueHash"] + ".jpg";
-                        photos.push(create_photo(row["id"], row["name"], imagepath, thumbpath));
-                    }
+                    var imagepath = process.env.PUBLIC_URL + collection_path + "/" + row["relativePath"] + "/" + row["name"];
+                    var thumbpath = process.env.PUBLIC_URL + collection_thumbs_path + "/" + row["uniqueHash"] + ".jpg";
+                    photos.push(create_photo(row["id"], row["name"], imagepath, thumbpath));
                 });
             }
             resolve(photos);
@@ -223,9 +219,7 @@ export class UserQuery {
 
 // This query will return database entries with the fields "id", "uniqueHash", "relativePath" (of the album) and "name" for each matching image.
 export function image_query_with_where(maybe_where) {
-    return "SELECT Images.id, Images.name, Images.uniqueHash, Albums.relativePath FROM Images INNER JOIN Albums ON Images.album=Albums.id LEFT JOIN ImageTags ON Images.id=ImageTags.imageid LEFT JOIN Tags ON ImageTags.tagid=Tags.id " + (maybe_where ? maybe_where : "");
-    // TODO: the following for some reason breaks the query:
-    //+ " GROUP BY Images.id;";
+    return "SELECT Images.id, Images.name, Images.uniqueHash, Albums.relativePath FROM Images INNER JOIN Albums ON Images.album=Albums.id LEFT JOIN ImageTags ON Images.id=ImageTags.imageid LEFT JOIN Tags ON ImageTags.tagid=Tags.id " + (maybe_where ? maybe_where : "" + " GROUP BY id;");
 }
 
 // This query will return database entries with the fields "id" and "relativePath" for each matching album.